College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Concept and Vocabulary Check - Page 750: 4

Answer

See below.

Work Step by Step

By substituting in: for $n=1$ the statement says that $2$ is a factor of $1^2+3\cdot1=1+3=4$ for $n=2$ the statement says that $2$ is a factor of $2^2+3\cdot2=4+6=10$ for $n=3$ the statement says that $2$ is a factor of $3^2+3\cdot3=9+9=18$ for $n=k+1$ the statement says that $2$ is a factor of $(k+1)^2+3\cdot(k+1)$, which can be simplified to $k^2+2k+1+3k+3=k^2+5k+4$
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