Answer
See below.
Work Step by Step
By substituting in: for $n=3$: $3+7+11=3(6+1)$
for $n=k+1$, before simplication: $3+7+11+...+(4(k+1)-1)=(k+1)(2(k+1)+1)$, which is equivalent to: $3+7+11+...+(4k+3)=(k+1)(2k+3)$,
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Concept and Vocabulary Check - Page 750: 3
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