## College Algebra (6th Edition)

$\displaystyle \frac{y^{2}}{25}-\frac{x^{2}}{9}=1$
The branches of the graph indicate that the transverse axis is vertical, the center is at the origin, so the form of the equation is $\displaystyle \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1$ From the graph, $a=5,$ $b=3$. $\displaystyle \frac{y^{2}}{25}-\frac{x^{2}}{9}=1$