College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.2 - Page 685: 30


$\displaystyle \frac{y^{2}}{25}-\frac{x^{2}}{9}=1$

Work Step by Step

The branches of the graph indicate that the transverse axis is vertical, the center is at the origin, so the form of the equation is $\displaystyle \frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1$ From the graph, $a=5,$ $b=3$. $\displaystyle \frac{y^{2}}{25}-\frac{x^{2}}{9}=1$
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