College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.2 - Page 685: 28

Answer

$\displaystyle \frac{x^{2}}{9}-\frac{y^{2}}{4}=1$

Work Step by Step

The branches of the graph indicate that the transverse axis is horizontal, the center is at the origin, the form of the equation is $\displaystyle \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$. From the graph, $a=3,$ $b=2$ $\displaystyle \frac{x^{2}}{9}-\frac{y^{2}}{4}=1$
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