College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.2 - Page 685: 25

Answer

See graph

Work Step by Step

We are given the hyperbola: $-y^2+x^2=2$ Bring the equation to the standard form: $\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1$ $\dfrac{x^2}{2}-\dfrac{y^2}{2}=1$ The transverse axis is parallel to the $x$-axis. Determine $h,k,a,b,c$: $h=0$ $k=0$ $a^2=2\Rightarrow a=\sqrt 2$ $b^2=2\Rightarrow b=\sqrt 2$ $c^2=a^2+b^2$ $c^2=2+2$ $c^2=4$ $c=2$ Determine the coordinates of the vertices: $(h-a,k)=(0-\sqrt 2,0)=(-\sqrt 2,0)$ $(h+a,k)=(0+\sqrt 2,0)=(\sqrt 2,0)$ Determine the coordinates of the co-vertices: $(h,k-b)=(0,0-\sqrt 2)=(0,-\sqrt 2)$ $(h,k+b)=(0,0+\sqrt 2)=(0,\sqrt 2)$ Determine the coordinates of the foci: $(h-c,k)=(0-2,0)=(-2,0)$ $(h+c,k)=(0+2,0)=(2,0)$ Graph the hyperbola:
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