College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Summary, Review, and Test - Review Exercises - Page 656: 8

Answer

Inconsistent system

Work Step by Step

Build the augmented matrix of the system of equations; $\begin{bmatrix}2&-3&1&|&1\\1&-2&3&|&2\\3&-4&-1&|&1\end{bmatrix}$ Bring the matrix to the row reduced echelon form: Add $-R_2$ to $R_1$: $\begin{bmatrix}1&-1&-2&|&-1\\1&-2&3&|&2\\3&-4&-1&|&1\end{bmatrix}$ Add $-R_1$ to $R_2$: $\begin{bmatrix}1&-1&-2&|&-1\\0&-1&5&|&3\\3&-4&-1&|&1\end{bmatrix}$ Add $-3R_1$ to $R_3$: $\begin{bmatrix}1&-1&-2&|&-1\\0&-1&5&|&3\\0&-1&5&|&4\end{bmatrix}$ Add $-R_2$ to $R_1$ and $R_3$: $\begin{bmatrix}1&0&-7&|&-4\\0&-1&5&|&3\\0&0&0&|&1\end{bmatrix}$ The last row shows that the system is inconsistent, therefore it has no solution.
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