College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Summary, Review, and Test - Review Exercises - Page 656: 22

Answer

$\left[\begin{array}{lll} -10 & -6 & 2\\ 16 & 3 & 4\\ -23 & -16 & 7 \end{array}\right]$

Work Step by Step

The product of an $m\times n$ matrix and an $n\times p$ matrix is an $m\times p$ matrix. The element in the ith row and $j$th column of $BA$ is found by multiplying each element in the $i$th row of $B$ by the corresponding element in the $j$th column of $A$ and adding the products. $B$ is a $3\times\underline{2}$ matrix, $A$ is $\underline{2}\times 3.$ $BA $ exists and is a $3\times 3$ matrix. $BA=\left[\begin{array}{lll} 0(2)-2(5) & 0(-1)-2(3) & 0(2)-2(-1)\\ 3(2)+2(5) & 3(-1)+2(3) & 3(2)+2(-1)\\ 1(2)-5(5) & 1(-1)-5(3) & 1(2)-5(-1) \end{array}\right]$ $=\left[\begin{array}{lll} -10 & -6 & 2\\ 16 & 3 & 4\\ -23 & -16 & 7 \end{array}\right]$
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