College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 654: 78

Answer

$\frac{x^2}{16}+\frac{y^2}{25}=1$

Work Step by Step

If we divide the equation by $400$, we obtain: $25x^2+16y^2=400\\ \frac{25x^2}{400}+\frac{16y^2}{400}=\frac{400}{400}\\ \frac{x^2}{16}+\frac{y^2}{25}=1$
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