Answer
See below.
Work Step by Step
a) If $y=0$, then $\frac{x^2}{9}=1\\x^2=9\\x=\pm3$
Thus the y-intercepts are $-3$ and $3$.
b) If $x=0$, then $\frac{y^2}{4}=1\\y^2=4\\y=\pm2$
Thus the x-intercepts are $-2$ and $2$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 654: 77
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