## College Algebra (6th Edition)

Solution set: $\{ ( -13t+5$ , $5t$ , $t )$ , $t\in \mathbb{R}\}$
Augmented matrix: $\left[\begin{array}{lllll} 1 & 2 & 3 & | & 5\\ 0 & 1 & -5 & | & 0 \end{array}\right]$ is already in row echelon form, so no row operations are necessary. The system is consistent and does not have a unique solution. Let $z=t, t\in \mathbb{R}$. Substituting into row 2, $y-5t=0$ $y=5t$ Substituting into row 1, $x+2(5t)+3t=5$ $x+13t=5$ $x=-13t+5$ Solution set: $\{ ( -13t+5$ , $5t$ , $t )$ , $t\in \mathbb{R}\}$