College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.2 - Page 540: 56

Answer

$\frac{5x^3-3x^2+7x-3}{(x^2+1)^2}$

Work Step by Step

$\frac{5x-3}{x^2+1}+\frac{2x}{(x^2+1)^2}=\frac{(5x-3)(x^2+1)}{(x^2+1)^2}+\frac{2x}{(x^2+1)^2}=\frac{(5x-3)(x^2+1)+2x}{(x^2+1)^2}=\frac{5x^3-3x^2+5x-3+2x}{(x^2+1)^2}=\frac{5x^3-3x^2+7x-3}{(x^2+1)^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions