Answer
$\frac{x+14}{x^2-2x-8}$
Work Step by Step
$\frac{3}{x-4}-\frac{2}{x+2}=\frac{3(x+2)}{(x-4)(x+2)}-\frac{2(x-4)}{(x-4)(x+2)}=\frac{3(x+2)-2(x-4)}{(x-4)(x+2)}=\frac{3x+6-2x+8}{x^2+2x-4x-8}=\frac{x+14}{x^2-2x-8}$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.2 - Page 540: 55
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