College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 530: 77

Answer

150 rooms without kitchens and 50 with kitchens

Work Step by Step

k = # of rooms with kitchens w = # of rooms without kitchens Total amount of rooms = 200 k + w = 200 Each room with kitchen facilities generates 100 (100k) Each room without kitchen facilities generates 80 (80w) Total revenue is 17000 100k + 80w = 17000 k + w = 200 can also be written w = 200 - k. Plug this into 100k + 80w = 17000 100k + 80(200 - k) = 17000 100k + 16000 - 80k = 17000 20k = 1000 k = 50 50 rooms with kitchens Plug k into k + w = 200 50 + w = 200 w = 150 150 rooms without kitchens
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