College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 531: 78

Answer

11 four-seated tables and 6 two-seated tables

Work Step by Step

t = # of two-seated tables f = # of four-seated tables Total number of tables = 17 t + f = 17 Each two-seated table has 2 customers Each four-seated table has 4 customers Total number of customers 2t + 4f = 56 t + f = 17 can be written as t = 17 - f. Plug this into 2t + 4f = 56 2(17 - f) + 4f = 56 34 - 2f + 4f = 56 34 + 2f = 56 2f = 22 f = 11 There are 11 four-seated tables Plug f into t + f = 17 t + 11 = 17 t = 6 There are 6 two-seated tables
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