College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 531: 79

Answer

The dimensions of the lot are 100ft x 80ft

Work Step by Step

l= length (ft) w = width (ft) Perimeter: 360 ft 2l + 2w = 360 Fencing is 20 per ft for the length of the fence (20l) Fencing is 8 per ft for the width of the fence (8 $\times$ 2w)
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