College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 530: 73

Answer

Each Mr. Goodbar has 264 calories and each Mounds bar has 258 calories

Work Step by Step

g = calories in one Mr. Goodbar m = calories in one Mounds g + 2m = 780 2g + m = 786 2g + m = 786 can be written as m = 786 - 2g. Plug this into g + 2m = 780 g + 2(786 - 2g) = 780 g + 1572 - 4g = 780 -3g = -792 g = 264 Each Mr. Goodbar has 264 calories Plug in g into g + 2m = 780 264 + 2m = 780 2m = 516 m = 258 Each Mounds bar has 258 calories
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