College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Mid-Chapter Check Point - Page 562: 19

Answer

$x=55$ textdegrees $y=35$ textdegrees

Work Step by Step

We can write the system of equations: $\begin{cases} x+y+90=180\\ x+3y+20=180 \end{cases}$ Rewrite the system: $\begin{cases} x+y=90\\ x+3y=160 \end{cases}$ Multiply Equation 1 by -1 and add it to Equation 2 to eliminate $x$ and determine $y$: $\begin{cases} -x-y=-90\\ x+3y=160 \end{cases}$ $-x-y+x+3y=-90+160$ $2y=70$ $y=\dfrac{70}{2}$ $y=35$ Determine $x$: $x+y=90$ $x+35=90$ $x=90-35$ $x=55$ The two angles are: 55 textdegrees, 35 textdegrees.
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