## College Algebra (6th Edition)

Let $x$ be the number of roses, then the number of canatations is $20-x$, thus the total cost is: $3x+1.5\cdot(20-x)=39\\3x+30-1.5x=39\\1.5x=9\\x=6$ Thus we have $6$ roses and $20-6=14$ carnatations.