Answer
$y=1000e^{1.988x}$
Work Step by Step
Use Basic Logarithmic Properties: $b^{\log_{b}x}=x$,
replacing b with e and x with $(7.3)^{x}$
$y=1000(7.3)^{x}$ is equivalent to $y=1000e^{\ln(7.3)^{x}}$\qquad
... now, by the Power Rule: $\log_{\mathrm{b}}\mathrm{M}^{\mathrm{p}}=\mathrm{p}\log_{\mathrm{b}}\mathrm{M}$
$y=1000e^{(\ln 7.3)x}$
Calculator:
$\ln 7.3\approx$1.98787434815 $\qquad$ ... round to 3 decimals
$\approx 1.988$,
$y=1000e^{1.988x}$
