College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.5 - Page 506: 39

Answer

The function models the data well for the values attributed to the year 2,010.

Work Step by Step

$$f(x) = \frac{12.57}{1 + 4.11e^{-0.026x}}$$ where $f(x)$ is the world population in billions and $x$ represents the amount of years after 1949. To compare the world population in the year 2010: $$f(x) = \frac{12.57}{1 + 4.11e^{-0.026(2,010 - 1,949)}}$$ $$f(x) = \frac{12.57}{1 + 4.11e^{-0.026(61)}} \approx 6.8$$ We can conclude that, if the world population is to be 6.9 billion in the year 2,010, then the model is only off by 100 million, which is a good estimate.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.