College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 491: 118

Answer

9 days, $(9.0, 0)$

Work Step by Step

Insert $P(x)=0$ and solve for x. $0=95-30\log_{2}x\qquad.../+30\log_{2}x$ $30\log_{2}x=95\qquad.../\div 30$ $\displaystyle \log_{2}x=\frac{95}{30}\qquad...$apply $2^{(...)}$ to both sides $ x=2^{95/30}\approx$8.97969638647$\approx 9.0$ days After 9.0 days, all the students will have forgotten... Since $P($9.0$)=0,$ the point on the graph is $(9.0, 0)$
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