College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 491: 117

Answer

2.8 days, $(2.8, 50)$

Work Step by Step

Insert $P(x)=40$ and solve for x. $40=95-30\log_{2}x\qquad.../-40+30\log_{2}x$ $30\log_{2}x=45\qquad.../\div 30$ $\log_{2}x=1.5\qquad...$apply $2^{(...)}$ to both sides $ x=2^{1.5}\approx$2.82842712475$\approx 2.8$ days After 2.8 days, only half the students recall... Since $P(2.8)=50,$ the point on the graph is $(2.8, 50)$
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