## College Algebra (6th Edition)

Insert the given $A,\ P,$ and $r$ into the formula and solve for t. $12, 000=8000e^{0.203t}\qquad.../\div 8000$ $1.5=e^{0.203t}\qquad .../$apply ln() to both sides.. $\ln 1.5=0.203t\qquad .../\div 0.203$ $t=\displaystyle \frac{\ln 1.5}{0.203}\approx$1.99736506457$\approx 2$ years