#### Answer

1 real zero,
2 imaginary (complex, nonreal) zeros

#### Work Step by Step

see Properties of Roots of Polynomial Equations (page 382)
1. If a polynomial equation is of degree $n$, then counting multiple roots separately, the equation has $n$ roots.
2. If $a+bi$ is a root of a polynomial equation with real coefficients $(b\neq 0)$, then the imaginary number $a-bi$ is also a root.
Imaginary roots, if they exist, occur in conjugate pairs.
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The graph (attached image) crosses the x-axis at x=3...
f has 1 real zero.
It has a total of 3 zeros, so two are conjugate complex numbers