Answer
Possible rational zeros = $\pm1, \pm2, \pm4, \pm8, \pm\dfrac{1}{3}, \pm\dfrac{2}{3}, \pm\dfrac{4}{3}, \pm\dfrac{8}{3}$
Work Step by Step
$f(x)=3x^4-11x^3-3x^2-6x+8$
The constant term is 8.
Factors of 8:$ \pm1, \pm2, \pm4, \pm8$
Factors of leading coefficient, 3: $\pm1, \pm2, \pm3$
Possible rational zeros = Factors of 8 $\div$ Factors of 3
Possible rational zeros = $\pm1, \pm2, \pm4, \pm8, \pm\dfrac{1}{3}, \pm\dfrac{2}{3}, \pm\dfrac{4}{3}, \pm\dfrac{8}{3}$
