College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.4 - Page 386: 5

Answer

Possible rational zeros = $\pm1, \pm2, \pm3, \pm6, \pm\dfrac{1}{2}, \pm\dfrac{3}{2}, \pm\dfrac{1}{4}, \pm\dfrac{3}{4}$

Work Step by Step

$f(x)=4x^4-x^3+5x^2-2x-6$ The constant term is -6. Factors of -6:$ \pm1, \pm2, \pm3, \pm6$ Factors of leading coefficient, 4: $\pm1, \pm2, \pm4$ Possible rational zeros = Factors of -6 $\div$ Factors of 4 Possible rational zeros = $\pm1, \pm2, \pm3, \pm6, \pm\dfrac{1}{2}, \pm\dfrac{3}{2}, \pm\dfrac{1}{4}, \pm\dfrac{3}{4}$
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