College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.4 - Page 386: 3


Possible rational zeros = $\pm1, \pm2, \pm3, \pm6, \pm\dfrac{1}{3}, \pm\dfrac{2}{3}$

Work Step by Step

$f(x)=3x^4-11x^3-x^2+19x+6$ The constant term is 6. Factors of 6:$ \pm1, \pm2, \pm3, \pm6$ Factors of leading coefficient, 3: $\pm1, \pm3$ Possible rational zeros = Factors of 6 $\div$ Factors of 3 Possible rational zeros = $\pm1, \pm2, \pm3, \pm6, \pm\dfrac{1}{3}, \pm\dfrac{2}{3}$
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