College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Test - Page 327: 23


f(-x)= x$^2$+ x-4 Neither even nor odd.

Work Step by Step

f(x)=x$^2$-x-4 f(-x)=(-x)$^2$-(-x)-4 f(-x)=x$^2$+x-4 -f(x)=-(x$^2$-x-4) -f(x)=-x$^2$+x+4 The function is neither even nor odd because f(-x) does not equal f(x) or -f(x).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.