Answer
f(-x)= x$^2$+ x-4
Neither even nor odd.
Work Step by Step
f(x)=x$^2$-x-4
f(-x)=(-x)$^2$-(-x)-4
f(-x)=x$^2$+x-4
-f(x)=-(x$^2$-x-4)
-f(x)=-x$^2$+x+4
The function is neither even nor odd because f(-x) does not equal f(x) or -f(x).