Answer
($\frac{f}{g}$)(x)=$\frac{x^2-x-4}{2x-6}$
D=(-$\infty$,3) U (3,$\infty$)
Work Step by Step
($\frac{f}{g}$)(x)=$\frac{f(x)}{g(x)}$
($\frac{f}{g}$)(x)=$\frac{x^2-x-4}{2x-6}$
2x-6$\ne$0
2x$\ne$6
x$\ne$3
Therefore the domain includes all real numbers except for 3.