College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Test - Page 327: 16

Answer

$f(x-1) = x^{2} -3x -1$

Work Step by Step

$f(x) = x^{2} - x - 4$ $f(x-1) = (x-1)^{2} - (x-1) - 4$ $= [x(x-1)-1(x-1) - x + 1 - 4$ $= x^{2} - 2x + 2 -x + 1 - 4$ $= x^{2} -3x + 3 - 4$ $= x^{2} -3x -1$
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