## College Algebra (6th Edition)

y=-$\frac{1}{4}$x-6
4x-y-6=0 y=4x-6 Therefore the slope of the desired line is -$\frac{1}{4}$ and contains the point (0, -6). y-y$_1$=m(x-x$_1$) y+6=-$\frac{1}{4}$(x-0) y=-$\frac{1}{4}$x-6