Answer
y=-$\frac{2}{3}$x-2
Work Step by Step
3x-2y-4=0
2y=3x-4
y=$\frac{3}{2}$x-2
Therefore the desired line has a slope of -$\frac{2}{3}$ and contains the point (0, -2).
y-y$_1$=m(x-x$_1$)
y+2=-$\frac{2}{3}$(x-0)
y=-$\frac{2}{3}$x-2
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