College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.4 - Page 267: 23

Answer

y=-$\frac{2}{3}$x-2

Work Step by Step

3x-2y-4=0 2y=3x-4 y=$\frac{3}{2}$x-2 Therefore the desired line has a slope of -$\frac{2}{3}$ and contains the point (0, -2). y-y$_1$=m(x-x$_1$) y+2=-$\frac{2}{3}$(x-0) y=-$\frac{2}{3}$x-2
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