Answer
y=-$\frac{1}{3}$x+$\frac{13}{3}$
Work Step by Step
m=$\frac{y_2-y_1}{x_2-x_1}$
m=$\frac{-9-0}{0-3}$
m=3
Therefore the slope of the desired line is -$\frac{1}{3}$
y-y$_1$=m(x-x$_1$)
y-6=-$\frac{1}{3}$(x+5)
y=-$\frac{1}{3}$x-$\frac{5}{3}$+6
y=-$\frac{1}{3}$x+$\frac{13}{3}$
