College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.1 - Page 224: 30

Answer

$g(-1) = 8$ $g(x+2) = x^{2} -6x - 19$ $g(-x) = x^{2} + 10x - 3$

Work Step by Step

$g(x) = x^{2} - 10x - 3$ $g(-1) = (-1)^{2} - 10(-1) - 3$ $= 1 + 10 - 3$ $= 11 - 3$ $= 8$ $g(x+2) = (x+2)^{2} - 10(x+2) - 3$ $= x^{2} + 4x + 4 - 10x - 20 - 3$ $= x^{2} -6x - 19$ $g(-x) = (-x)^{2} - 10(-x) - 3$ $= x^{2} + 10x - 3$
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