Answer
$R_{1}= \frac{RR_{2}}{R_{2}-R}$
Work Step by Step
$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$
Solve for $R_{1}$
$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$
$\frac{1}{R}-\frac{1}{R_{2}}=\frac{1}{R_{1}}$
Take LCD,
$\frac{R_{2}-R}{RR_{2}}=\frac{1}{R_{1}}$
$R_{1}= \frac{RR_{2}}{R_{2}-R}$