College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.3: 66

Answer

$b=\frac{2A}{h}-a$

Work Step by Step

Area of Trapezoid $A=\frac{1}{2}h (a+b)$ Solving for b $A=\frac{h}{2} (a+b)$ Multiply both sides by $\frac{2}{h}$ $\frac{2}{h} \times A=\frac{2}{h} \times \frac{h}{2} (a+b)$ $\frac{2A}{h} = a+b$ Add $-a$ to both sides $\frac{2A}{h}-a = a+b-a$ $\frac{2A}{h}-a = b$ $b=\frac{2A}{h}-a$
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