College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.3 - Page 135: 71

Answer

$I=\frac{E}{(R+r)}$

Work Step by Step

Factor out $I$ from the first two terms. Then divide both sides by $R+r$. $IR+Ir=E$ for $I$ $I(R+r)=E$ $I=\frac{E}{(R+r)}$
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