## College Algebra (6th Edition)

Write an equation. $2y_{1}-3y_{2}=4y_{3}-8$ Substitute for y1, y2 and y3. Solve for x. 2(2.5) - 3(2x + 1) = 4x - 8 5 - 6x - 3 = 4x - 8 10 = 10x x = 1