## College Algebra (6th Edition)

Write an equation. $3y_{1}-5y_{2}=y_{3}-22$ Substitute for y1, y2, and y3. Solve for x. 3(2x + 6) - 5(x + 8) = x - 22 6x + 18 - 5x - 40 = x - 22 X - 22 = x - 22 -22 = -22 x = All real numbers