College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.3 - Page 133: 11

Answer

x = 3/2

Work Step by Step

Write an equation. $y_{1}+2=y_{2}$ Substitute for y1 and y2. Solve for x. (13x - 4) + 2 = 5x + 10 13x - 2 = 5x + 10 8x = 12 x = 3/2
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