College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 57: 78

Answer

$-15y^{19/10} -20y^{13/10}$

Work Step by Step

$\begin{array}{ l l } =-15y\cdot y^{9/10} -20y\cdot y^{3/10} & \begin{array}{l} \mathrm{Apply\ the\ distributive\ property}\\ a( b+c) =ab+ac \end{array}\\ & \\ =-15y^{9/10+10/10} -20y^{3/10+10/10} & \begin{array}{l} \mathrm{Apply\ the\ rule}\\ a^{b} \cdot a^{c} =a^{b+c} \end{array}\\ & \\ =-15y^{19/10} -20y^{13/10} & \mathrm{Add\ fractions\ to\ simplify} \end{array}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.