College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 57: 76

Answer

$3p^{3}+9p^{6}$

Work Step by Step

Using the Distributive Property, the given expression, $ p^{11/5}(3p^{4/5}+9p^{19/5}) ,$ simplifies to \begin{array}{l}\require{cancel} p^{11/5}(3p^{4/5})+p^{11/5}(9p^{19/5}) \\\\= 3p^{\frac{11}{5}+\frac{4}{5}}+9p^{\frac{11}{5}+\frac{19}{5}} \\\\= 3p^{\frac{15}{5}}+9p^{\frac{30}{5}} \\\\= 3p^{3}+9p^{6} .\end{array}
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