College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 39: 66


(3$z^{3}$ + 4$y^{4}$)(9$z^{6}$ - 12$z^{3}y^{4}$ + 16$y^{8}$)

Work Step by Step

27$z^{9}$ + 64$y^{12}$ is a sum of cubes, so we write it as a sum of cubes and factor: $(3z^{3})^{3}$ + $(4y^{4})^{3}$ = (3$z^{3}$ + 4$y^{4}$)($(3z^{3})^{2}$ - 3$z^{3}$( 4$y^{4}$) + $(4y^{4})^{2}$ ) = (3$z^{3}$ + 4$y^{4}$)(9$z^{6}$ - 12$z^{3}y^{4}$ + 16$y^{8}$)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.