#### Answer

(3 - r)(9 + 3r + $r^{2}$)

#### Work Step by Step

27 - $r^{3}$ is a difference of cubes, so we write it as a difference of cubes and factor:
$3^{3}$ - $r^{3}$
(3 - r)($3^{2}$ + 3r + $r^{2}$)
= (3 - r)(9 + 3r + $r^{2}$)

Published by
Pearson

ISBN 10:
0321671791

ISBN 13:
978-0-32167-179-0

(3 - r)(9 + 3r + $r^{2}$)

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