Answer
(2m - 3n)(4$m^{2}$ + 6mn + 9$n^{2}$)
Work Step by Step
8$m^{3}$ - 27$n^{3}$ is a difference of cubes, so we write it as a difference of cubes and factor:
$(2m)^{3}$ - $(3n)^{3}$
= (2m - 3n)($(2m)^{2}$ + 2m(3n) + $(3n)^{2}$)
= (2m - 3n)(4$m^{2}$ + 6mn + 9$n^{2}$)
