Answer
$12, 10, 8, 6, 4$
Work Step by Step
From the given sequence, we have: $n=1,2,3,4,5$ and $d=-2$; $a_2=10$
$a_1=a_2-d=10-(-2)=10+2=12$
The succeeding terms can be computed by adding the common difference $-2$:
$a_3=a_2+(-2)=10-2=8\\a_4=a_3+(-2)=8-2=6\\a_5=a_4+(-2)=6-2=4$
Hence, the first $5$ terms are $12, 10, 8, 6, 4$
