Answer
$6, 12, 24, 48, 96$
Work Step by Step
As we know that the common ratio of a geometric sequence can be written as: $a_{n+1}=a_n\cdot r$
From the given sequence, we have: $a_1=6$ and $r=2$
$a_2=(6)(2)=12$
In similar way, we can have the remaining terms of a given sequence as:
$a_3=(12)(2)=24\\a_4=(24)(2)=48\\a_5=(48)(2)=96$
Hence, the first $5$ terms are $6, 12, 24, 48, 96$
