College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Review Exercises - Page 697: 7

Answer

$4, 4.5, 5, 5.5, 6$

Work Step by Step

Th first term is $4$ so $a_1=4$. The sum must be $25$ Using $d$ as the common difference, then the next $4$ terms of the sequence are: $a_2=a_1+d =4+d \\a_3=a_1+2d =4+2d\\a_4=a_1+3d =4+3d\\a_5=a_1+4d =4+4d$ Since the sum of the $5$ terms is $25$, then $a_1+a_2+a_3+a_4+a_5=25$ Thus, $4+(4+d)+(4+2d)+(4+3d)+(4+4d)=25\\ 10d+20=25\\ 10d=25-20\\ 10d=5\\ d=0.5$ Substituting the value of $d$ into each term, we get the $5$ to be: $a_1=4\\ a_2=4+0.5=4.5\\ a_3=4.5+0.5=5\\ a_4=5+0.5=5.5\\ a_5=5.5+0.5=6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.