College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 28



Work Step by Step

Divide both sides by 5. $(1.024)^{x-1900}=\frac{9}{6}$ Take the logarithm of both sides. $(x-1900)\log1.024=\log\frac{3}{2}$ Divide both sides by $\log1.024$ and solve for $x$. $x=1900+\frac{\log\frac{3}{2}}{\log1.024}\approx1917.0963$
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