College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 446: 24



Work Step by Step

Given Expression $5(1.2)^{3x-2}+1=7$ Subtract 1 from both sides. $5(1.2)^{3x-2}=6$ Divide both sides by 5. $1.2^{3x-2}=\frac{6}{5}$ Take log of both sides. $\log1.2^{3x-2}=\log\frac{6}{5}$ Power Rule of logarithms. $(3x-2)\log1.2=\log\frac{6}{5}$ Solve for $x$. $x=((\frac{\log\frac{6}{5}}{\log1.2})+2)\div3$ $x=1$
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